Abstract
In this paper we consider the quartic diophantine equation 3(y2 – 1) = 2x2(x2 – 1) in integers x and y. We show that this equation does not have any other solutions (x, y) with x¿0 than those given by x = 0,1,2,3,6,91. Two approaches are emphasized, one based on diophantine approximation techniques, the other depends on the structure of certain quartic number fields.
Original language | English |
---|---|
Pages (from-to) | 97-114 |
Journal | Proceedings of the Edinburgh Mathematical Society. Series II |
Volume | 39 |
Issue number | 1 |
DOIs | |
Publication status | Published - 1996 |